Hi,<br><br>I have a tool with a &lt;code file=&quot;my_script.py&quot;/&gt; tag and in that code file I&#39;m trying to get the tool dirpath where that script and the tool XML exist.  I&#39;ve tried:<br><br><span style="font-family: courier new,monospace;">os.path.abspath(os.path.dirname(sys.argv[0]))</span><br style="font-family: courier new,monospace;">
<span style="font-family: courier new,monospace;">os.path.abspath(os.path.dirname(__file__))</span><br><br>And both don&#39;t work as expected. Is there a galaxy class I could import which will have the tool directory path?<br>
<br>regards,<br>Leandro<br><br>