Hey, I'm writing a XML for a tool that produces a number of output files. As the number is not known before the tool is run, I used the strategy outlined here: http://wiki.galaxyproject.org/Admin/Tools/Multiple%20Output%20Files#Numbe... First, I tried my tool definition in a galaxy instance in a virtual machine to not interrupt our production instance (we have a local instance set up). Here, everything worked fine. When trying the same code in our production galaxy instance, it didn't: Regardless of how many output files were produced, only one appears in the history. (the first one, corresponding to "output1" in the references wiki entry). When looking at the temp directory provided to the tool by galaxy ("$__new_file_dir__" in the wiki, it always points to "galaxy-dist/database/tmp/"), the additional output files have been created by my tool and are named correctly (e.g. primary_123_output2_visible_fastq, primary_123_output3_visible_fastq, …) Both instances are new, based on release_2013.06.03. Is there any setting in galaxy somewhere that could prevent this from working? Thanks for your help Chris PS: I wrote a little python script that just creates multiple output files, and the discrepancy between the two instances is reproducible. Here is the code for the python script and the corresponding XML: ####### import subprocess import argparse import os def main(): parser = argparse.ArgumentParser() parser.add_argument('-i', type=int) parser.add_argument('output1') parser.add_argument('output1_id') parser.add_argument('out_dir') args = parser.parse_args() print 'Wrapper arguments:', args with open(args.output1, 'w') as f: f.write('output1') for i in range(2, args.i+1): name = 'output%i'%i file_type = 'text' fname = '%s_%s_%s_%s_%s' % ('primary', args.output1_id, name, 'visible', file_type) with open(os.path.join(args.out_dir, fname), 'w') as f: f.write('output%i'%i) if __name__ == "__main__": main() ############################ ########################### <tool name="MultiOutTest" id="multiouttest"> <description>Multiple Outputs test</description> <command interpreter="python"> multiout.py -i $how_many $output1 $output1.id $__new_file_path__ </command> <inputs> <param name="how_many" type="integer" value="2" label="How many output files?"/> </inputs> <outputs> <data name="output1" format="txt"/> </outputs> <help> This is some help text. </help> </tool> ################################# -- Dr. Christoph Malisi Computomics GmbH & Co. KG Sand 14 · 72076 Tübingen · Germany http://computomics.com