Hi,
I'm looking for the correct syntax to achieve the following:
<data type="data" format="txt" name="loh" label="${tool.name} result on ${on_string} (loh) " > <filter>outtype == "0" || outttype == "2" </filter> </data> <data type="data" format="txt" name="cnv" label="${tool.name} result on ${on_string} (loh) " > <filter>outtype == "1" || outttype == "2" </filter> </data>
I tried the above, with and without parentheses, but it creates the second dataset also when outtype == 0. Is this type of dual filtering possible?
Best,
Geert
On Fri, Jan 31, 2014 at 10:52 AM, Geert Vandeweyer geert.vandeweyer2@uantwerpen.be wrote:
Hi,
I'm looking for the correct syntax to achieve the following:
<data type="data" format="txt" name="loh" label="${tool.name} result on ${on_string} (loh) " > <filter>outtype == "0" || outttype == "2" </filter>
</data> <data type="data" format="txt" name="cnv" label="${tool.name} result on ${on_string} (loh) " > <filter>outtype == "1" || outttype == "2" </filter> </data>
I tried the above, with and without parentheses, but it creates the second dataset also when outtype == 0. Is this type of dual filtering possible?
Rather than the logical or, have you tried outtype != "1", and outtype != "0" instead?
(I am assuming there are only three values for outtype, 0, 1 and 2.)
Peter
Il 2014-01-31 11:52 Geert Vandeweyer ha scritto:
Hi,
I'm looking for the correct syntax to achieve the following:
<data type="data" format="txt" name="loh" label="${tool.name} result on ${on_string} (loh) " > <filter>outtype == "0" || outttype == "2" </filter>
</data> <data type="data" format="txt" name="cnv" label="${tool.name} result on ${on_string} (loh) " > <filter>outtype == "1" || outttype == "2" </filter> </data>
I tried the above, with and without parentheses, but it creates the second dataset also when outtype == 0. Is this type of dual filtering possible?
I don't know if this is the reason, but you seem to have a typo:
outttype == "2"
should be
outtype == "2"
Best, Nicola
Hi,
Thanks for the quick suggestions.
The typo didn't exists in the original code, so that didn't solve it unfortunately. I fixed it for now by using the negative filter (!=), suggested by Peter.
Best,
Geert
On 01/31/2014 12:09 PM, Nicola Soranzo wrote:
Il 2014-01-31 11:52 Geert Vandeweyer ha scritto:
Hi,
I'm looking for the correct syntax to achieve the following:
<data type="data" format="txt" name="loh" label="${tool.name} result on ${on_string} (loh) " > <filter>outtype == "0" || outttype == "2" </filter>
</data> <data type="data" format="txt" name="cnv" label="${tool.name} result on ${on_string} (loh) " > <filter>outtype == "1" || outttype == "2" </filter> </data>
I tried the above, with and without parentheses, but it creates the second dataset also when outtype == 0. Is this type of dual filtering possible?
I don't know if this is the reason, but you seem to have a typo:
outttype == "2"
should be
outtype == "2"
Best, Nicola ___________________________________________________________ Please keep all replies on the list by using "reply all" in your mail client. To manage your subscriptions to this and other Galaxy lists, please use the interface at: http://lists.bx.psu.edu/
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Hi,
something like that is also possible:
(( params['settingsType'] == "custom" and params['unmapped_read_file'] is True ))
So I assume:
outtype == "0" or outtype == "2"
will also work. Cheers, Bjoern
2014-01-31 Geert Vandeweyer geert.vandeweyer2@uantwerpen.be:
Hi,
Thanks for the quick suggestions.
The typo didn't exists in the original code, so that didn't solve it unfortunately. I fixed it for now by using the negative filter (!=), suggested by Peter.
Best,
Geert
On 01/31/2014 12:09 PM, Nicola Soranzo wrote:
Il 2014-01-31 11:52 Geert Vandeweyer ha scritto:
Hi,
I'm looking for the correct syntax to achieve the following:
<data type="data" format="txt" name="loh" label="${tool.name} result on ${on_string} (loh) " > <filter>outtype == "0" || outttype == "2" </filter>
</data> <data type="data" format="txt" name="cnv" label="${tool.name} result on ${on_string} (loh) " > <filter>outtype == "1" || outttype == "2" </filter> </data>
I tried the above, with and without parentheses, but it creates the second dataset also when outtype == 0. Is this type of dual filtering possible?
I don't know if this is the reason, but you seem to have a typo:
outttype == "2"
should be
outtype == "2"
Best, Nicola ___________________________________________________________ Please keep all replies on the list by using "reply all" in your mail client. To manage your subscriptions to this and other Galaxy lists, please use the interface at: http://lists.bx.psu.edu/
To search Galaxy mailing lists use the unified search at: http://galaxyproject.org/search/mailinglists/
--
Geert Vandeweyer, Ph.D. Department of Medical Genetics University of Antwerp Prins Boudewijnlaan 43 2650 Edegem Belgium Tel: +32 (0)3 275 97 56 E-mail: geert.vandeweyer@ua.ac.be http://ua.ac.be/cognitivegenetics http://www.linkedin.com/in/geertvandeweyer
Please keep all replies on the list by using "reply all" in your mail client. To manage your subscriptions to this and other Galaxy lists, please use the interface at: http://lists.bx.psu.edu/
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